网络编程 发布日期：2024/10/1 浏览次数：1
废话不多说了，直接给大家贴代码了，具体代码如下所示：
<div style="position:relative;width:380px;">
<iframe id="t_load" name="t_load" style="display: none"></iframe>
<form action="" method="post" enctype="multipart/form-data" name="form1" target="t_load">
<input type='text' name='textfield' id='textfield' style="height:22px; border:2px solid #cdcdcd; width:230px; border-radius:50px;" />
<input type='button' value='浏览...' style="display: inline-block;
margin-bottom: 0;
font-size: 14px;
border-radius: 4px;
padding: 6px 12px;
margin: 2px 2px;
border: 1px solid #357ebd;
background: #1b9ad5;
color: #fff;" />
<input type="file" name="file1" accept="image/jpeg, image/gif" id="file1" onchange="document.getElementById('textfield').value=this.value" style="position:absolute; top:5px; right:74px; height:27px; filter:alpha(opacity:0);opacity: 0;width:300px" />
<input type="button" name="button" onclick="mysubmit()" value="上传" style="display: inline-block;
margin-bottom: 0;
font-size: 14px;
border-radius: 4px;
padding: 6px 12px;
margin: 2px 2px;
border: 1px solid #357ebd;
background: #1b9ad5;
color: #fff;">
</form>
</div>
<div style="display:none;color:#6D6D72;font-size: 20px;" id="res"></div>
<script>
function mysubmit() {
var a = document.getElementById("textfield").value;
if(a == "") {
alert("请上传文件");
return;
}
document.form1.submit();
ajaxsend();
}
function ajaxsend() {
var xmlHttp;
if(window.ActiveXObject) {
xmlHttp = new ActiveXObject("Msxml2.XMLHTTP");
} else {
xmlHttp = new XMLHttpRequest();
}
xmlHttp.open("post", "upload", true);
xmlHttp.onreadystatechange = function() {
xmlHttp.readyState;
if(xmlHttp.readyState == 4) {
res.innerHTML = "上传成功！";
setTimeout(function() {
res.innerHTML = "";
}, 2000);
} else {
document.getElementById("res").style.display = "inline";
}
}
xmlHttp.send();
var obj = document.getElementById('textfield');
obj.outerHTML = obj.outerHTML;
}
</script>
总结
以上所述是小编给大家介绍的JS实现浏览上传文件的代码，希望对大家有所帮助，如果大家有任何疑问请给我留言，小编会及时回复大家的。在此也非常感谢大家对网站的支持！